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From: Jonathan Morton <chromatix99@gmail.com>
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To: Stephen Hemminger <shemminger@vyatta.com>
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Subject: Re: [Bloat] Goodput fraction w/ AQM vs bufferbloat
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On 7 May, 2011, at 1:10 am, Stephen Hemminger wrote:

> Rate <=3D (MSS/RTT)*(1 / sqrt{p})
>=20
> where:
> Rate: is the TCP transfer rate or throughputd
> MSS: is the maximum segment size (fixed for each Internet path, =
typically 1460 bytes)
> RTT: is the round trip time (as measured by TCP)
> p: is the packet loss rate.=20

So if the loss rate is 1.0 (100%), the throughput is MSS/RTT.  If the =
loss rate is 0, the throughput goes to infinity.  That doesn't seem =
right to me.

 - Jonathan