Eric Dumazet <eric.dumazet@gmail.com> writes:

> I guess so. It must travel through the old_flows list from the tail to
> the head (so each flows in old_flows must be serviced by one quantum),
> to get the right to be declared as 'empty' and gain the honor to get
> promoted to 'new_flows' next time a packet is enqueued.
>
> If all flows are slow, but the queue can still build up, because there
> are too many flows for the possible bandwidth, than all flows are
> actually considered as thick, as if we had a single RR queue. (the
> old_flows).

Right, that makes sense. Everything is relative. Thanks for clearing
things up! :)


-Toke

-- 
Toke Høiland-Jørgensen
toke@toke.dk